I have an array of dates:

dates: 
  [ { start: '30.05.2022 02:30:00', end: '30.05.2022 03:30:00' } 
  , { start: '30.05.2022 02:34:01', end:  '3.06.2022 04:34:01' } 
  ]

What I want is to make the start of the second item of an array to be the end of the first item of an array and without breaking duration. The desired result should look like this:

dates: 
  [ { start: '30.05.2022 02:30:00', end: '30.05.2022 03:30:00' } 
  , { start: '30.05.2022 03:30:00', end:  '3.06.2022 05:30:00' } 
  ] 

I've tried to implement my solution, but it gives incorrect result, because duration of momentjs exceeds 24 hours:

const dateFormat = 'DD.MM.YYYY HH:mm:ss'

const parseDateByMoment= (dateString) => {
  return moment(dateString, dateFormat)
}

const convertDateToString= (dateString) => {
  return dateString.format(dateFormat)

}

const addOrSubtractDate = (startDate, endDate, isAdding) => {
  const startDateDuration = moment.duration(startDate.format("HH:mm:ss"))
  const endDateDuration = moment.duration(endDate.format("HH:mm:ss"))
  
  const result = isAdding 
    ? endDateDuration   startDateDuration
    : endDateDuration - startDateDuration
  return moment.duration(result)
}

const formatToTime = (diff) => {
  return moment.utc(diff).format("HH:mm:ss.SSS");
}

const makeSequentialTimeInTracks = (dates) => {
    dates.forEach((aDate, index) => {
        if (index !== 0) {
      let prevEndDate = dates[index - 1].end
      prevEndDate = parseDateByMoment(prevEndDate)
      aDate.start = convertDateToString(prevEndDate)
      // console.log('aDate.start is', aDate.start)      
      
      const start = parseDateByMoment(aDate.start)
      const durationStart = moment.duration(start.format("HH:mm:ss"))
      console.log('2. aDate.start is', start)

      let end = parseDateByMoment(aDate.end)
      const durationEnd =  moment.duration(end.format("HH:mm:ss"))
      console.log('2. aDate.end is', end)

      let difference = addOrSubtractDate(start, end, false)
      difference = moment(difference)
      let durationDifference = moment.duration(difference.format("HH:mm:ss"))
      console.log('durationDifference', 
        moment.duration(durationDifference))

      const temp = start.clone()
      console.log('2. temp is', temp)
      temp.startOf('day').add(difference)
      console.log('temp', temp.format(dateFormat))
      // aDate.end = convertDateToString(addOrSubtractDate(start, difference, true))
        }
  });
  
  return dates
}


const sequantialTime = makeSequentialTime(dates)
console.log(dates)

Any soultion with pure JavaScript or momentjs library will be highly appreciated.

CodePudding user response：

"simply" do

const makeSequentialTime = (() => // IIFE closure 
  {
  const // ---------------------------- utilities functions
    pad = n => n > 9 ? n : '0' n // min 2 digits
  , getDateUTC = DMY_hms =>     // date string conversion to UTC (time zone = 0)
      {
      let [D,M,Y,h,m,s] = DMY_hms.split(/\.|\s|\:/).map(Number)
      return new Date(Date.UTC(Y,--M,D,h,m,s,0))
      }
  , getDate_DMY_hms = dte =>     // UTC date conversion to DMY_hms format
      ( dte.getUTCDate()            '.'
        pad(dte.getUTCMonth()  1)   '.'
        dte.getUTCFullYear()        ' '
        pad(dte.getUTCHours())      ':'
        pad(dte.getUTCMinutes())    ':'
        pad(dte.getUTCSeconds())
    ) ;
  return (dates) =>  // main function
    {
    let
      d0_end    = getDateUTC(dates[0].end   )  
    , d1_start  = getDateUTC(dates[1].start )
    , d1_end    = getDateUTC(dates[1].end   )
    , sDelta_d1 = Math.abs(d1_start - d1_end) / 1000
      ;
    d0_end.setSeconds(d0_end.getSeconds()   sDelta_d1)

    Object.assign( dates[1], { start: dates[0].end
                             , end: getDate_DMY_hms(d0_end) })
    }
  })();


// -------------------------------------- test :

const objX = 
  { dates: 
    [ { start: '30.05.2022 02:30:00', end: '30.05.2022 03:30:00' } 
    , { start: '30.05.2022 02:34:01', end:  '3.06.2022 04:34:01' } 
  ] }

makeSequentialTime( objX.dates )

console.log ( 'result:\n'   JSON.stringify( objX.dates ).replace('},{','}\n,{') )

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