Here is part of my data
759 L 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0
760 Y 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0
761 H 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0
762 T 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0
763 T 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0
764 D 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
765 R 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
766 F 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0
767 W 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0
768 A 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
769 N 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
770 C 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
771 L 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0
772 G 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0
773 Y 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0
774 S 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0
775 H 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0
776 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
777 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
778 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
779 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
780 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
781 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
782 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
783 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
784 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
785 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
786 X 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
I want to delete last four 0s starting from line 776 to the end so that the column number matches with the previous rows. The delimiters are whitespace. I know for all rows, I can use
cut -f 21-
but how to How can I make it with specific rows with whitespace as delimiter? Thanks
CodePudding user response：
If those are actual line numbers, then perhaps you just want:
awk 'NR>775{NF=22}1' input-file
If those numbers are not line numbers, but are data in the first column, then perhaps you want:
awk '$1>775{NF=22}1' input-file