Get a string if two words not from the string match-CodePudding

On a Linux system I have some output like this:

Subject = CN=User_A,OU=users
Status = Valid   Kind = IKE   Serial = 98505   DP = 9
Not_Before: Wed Jun 15 13:53:55 2022   Not_After: Sun Jun 25 08:25:20 2023

Subject = CN=User_B,OU=users
Status = Valid   Kind = IKE   Serial = 98934   DP = 8
Not_Before: Sun Apr 18 18:24:16 2021   Not_After: Fri Apr 21 18:24:16 2023

I can use | grep 2022 | grep Jun to find certain data, but how can get Subject line in the output? I need to get the username whose certificate is about to expire ) Something like "Show me the Subject if "grep 2022 | grep Jun"".

Thank you in advance!

CodePudding user response：

What about this:

grep -B 2 "2022" test.txt | grep -o "CN=[A-Za-z0-1_]*" | cut -c 4-

grep -B 2     // show the matching line and two lines before too.
[A-Za-z0-1_]* // any character, being letters, digits and an underscore
grep -o "CN=[...]" 
              // show only the part, containing "CN=", followed by ...
cut -c 4-     // instead of "CN=...", only show "..." (starting at 4th character)

CodePudding user response：

Using grep

$ grep -m2 -e '^Subject' -e 'Jun' -e '2022' input_file
Subject = CN=User_A,OU=users
Not_Before: Wed Jun 15 13:53:55 2022   Not_After: Sun Jun 25 08:25:20 2023

Using sed

$ sed -n '/^Subject/{p;:a;n;/Jun\|2022/p;ba}' input_file
Subject = CN=User_A,OU=users
Not_Before: Wed Jun 15 13:53:55 2022   Not_After: Sun Jun 25 08:25:20 2023