Why this function that print array in reverse doesn't work-CodePudding

I'm trying to make a function that print array in reverse, but it doesn't work for me.

this is what I wrote (on online C compiler site):

#include <stdio.h>

void print_reversed(int* a)
{
    
    if (a[0]==0) {
        break;
    }
    print_reversed(&a[1]);
    printf("%d", a[0]);
}    
   

int main()
{
    int array [7] = {1, 2, 3, 4, 5, 6, 0};
    print_reversed(&array[0]);
    return 0;
}

0 indicate the end of the array.

I know there is a problem with the break statement but I don't know how to solve it.

I know there are other solutions but I need to solve it in that method.

(I'm learning the basic so maybe it stupid question).

thanks a lot!

CodePudding user response：

You are getting this error or similar:

<source>: In function 'print_reversed':
<source>:7:9: error: break statement not within loop or switch
    7 |         break;

As it says, break only works in a loop or a switch statement.

To return from a function, you want return.