From a group of people according to the height and weight for two parameters optimal select one or more, this is how make, totally have no idea, someone to give directions, give a way of thinking, thanks
CodePudding user response:
You don't give preferential standard think how can I help you
CodePudding user response:
If (height & gt; 175 and height & lt; 190) and (weight & lt; 80 and weight & gt; 65) then
Msgbox "who conform to the standards... "
endif
CodePudding user response:
refer to the second floor Topc008 response: if (height & gt; 175 and height & lt; 190) and (weight & lt; 80 and weight & gt; 65) then Msgbox "who conform to the standards... " Endif if you are a lesbian CodePudding user response:
Under the science Formula here: http://baike.baidu.com/view/966047.htm CodePudding user response:
reference Sandrer reply: 3/f Quote: refer to the second floor Topc008 response: If (height & gt; 175 and height & lt; 190) and (weight & lt; 80 and weight & gt; 65) then Msgbox "who conform to the standards... " Endif if you are lesbian? as a way of thinking on YaoYao CodePudding user response:
reference 4 floor caozhy response: under the science Formula here: HTTP://http://baike.baidu.com/view/966047.htm I calculate a 25, overweight CodePudding user response:
reference Sandrer reply: 3/f Quote: refer to the second floor Topc008 response: If (height & gt; 175 and height & lt; 190) and (weight & lt; 80 and weight & gt; 65) then Msgbox "who conform to the standards... " Endif if you are lesbian? Entertainment, standard of equality between men and women, too CodePudding user response:
Body mass index (BMI) ^ 2=weight (kg) present height (m) EX: 70 kg present (1.75 x 1.75)=22.86 Example: For example, a person's height is 1.75 meters, weight is 68 kg, his BMI=68/(1.75 ^ 2)=22.2 (kg/m ^ 2) when the BMI is 18.5 ~ 23.9 belongs to the normal, CodePudding user response:
reference 4 floor caozhy response: under the science Formula here: HTTP://http://baike.baidu.com/view/966047.htm Thank you, give a way of thinking,