How can I add an additional class inheritance to an existing one, but with different number of argum-CodePudding

I have an existing class TSEparser that inherits from a parent class Subparser, but now I want to add another parent class (SubparserMixin) to class TSEparser. However, the problem is that the arguments passed by the initial inheritance gets in the way of this new inheritance- how can I fix this?

i.e:

class Subparser: 
    def __init__(self, filename, data_group, **kwargs):
        self.data_group = data_group
        self.filename = filename
        self.__dict__.update(kwargs)


class TSEparser(Subparser):
    def __init__(self, filename, data_group, **kwargs):
        super().__init__(filename, data_group, **kwargs)

Now I want to add another parent class SubparserMixin so we have class TSEparser(Subparser, SubparserMixin), however Subparsermixin looks like this:

class SubparserMixin:

    def __init__(self):
        self.subparsers = {}
        self.context = PacketContext

Is there some way I can inherit separately from both Parent Classes? Something like this:

class TSEparser(Subparser):
    def __init__(self, filename, data_group, **kwargs):
        super(Subparser).__init__(filename, data_group, **kwargs)
        super(SubparserMixin).__init__()

I know the syntax is not correct but I hope it is clear what I am trying to do!

Following the answer below, would my class read:

class TSEparser(Subparser):
    def __init__(self, filename, data_group, **kwargs):
        Subparser.__init__(filename, data_group, **kwargs)
        SubparserMixin.__init__()

Because now, the SubparserMixin.init() is being highlighted as not enough arguments being passed in! Or the right bracket is highlighted in Pycharm- I believe due to the lack of arguments.

CodePudding user response：

You can specify which class' constructor gets called by simply using its name. So in your example you can just do

class TSEparser(Subparser, SubparserMixin):
    def __init__(self, filename, data_group, **kwargs):
        Subparser.__init__(self, filename, data_group, **kwargs)
        SubparserMixin.__init__(self)

There is no good and easy way to make this work using super. You can check out this question for more detail. super normally takes care of calling the proper classes for you. If you want to call the __init__ of a specific class manually (e.g. because the required arguments are different), you need to call it directly using its name as shown above.

Edit: My code example mistakenly didn't pass self when calling the base __init__ methods. Note that this is a difference between calling by super and directly by base class. super doesn't require self, while direct calling does.