creating a list of files with file absolute path in linux-CodePudding

I have a large sum of files (~50000 files).

ls /home/abc/def/

file1.txt
file2.txt
file3.txt
.........
.........
file50000.txt

I want to create a CSV file with two columns: first column provides the filename and the second provides the absolute file path as:

output.csv

file1.txt,/home/abc/def/file1.txt
file2.txt,/home/abc/def/file2.txt
file3.txt,/home/abc/def/file3.txt
.........................
.........................
file50000.txt,/home/abc/def/file50000.txt

How to do this with bash commands. I tried with ls and find as

find /home/abc/def/ -type f -exec ls -ld {} \; | awk '{ print $5, $9 }' > output.csv

but this gives me absolute paths. How to get the output as shown in output.csv above

CodePudding user response：

You can get both just the filename and the full path with GNU find's -printf option:

find /home/abc/def -type f -printf "%f,%p\n"

Pipe through sort if you want sorted results.

CodePudding user response：

How about:

$ find /path/ | awk -F/ -v OFS=, '{print $NF,$0}'

Add proper switches to find where needed.