sort file of multiple numbers with text behind them-CodePudding

good evening everyone, I would like to help specifically with the sort

the data is always on a different line and the text is behind the numbers

20:10:20 text
2:10:20 text
1:10:20 text
22:10:1 text
21:10:19 text
20:10:1 text

and they need to arrange it by numbers

so if the input is the example above, I expect the output to sort all numbers 0[2]

I am looking for this

1:10:20 text
2:10:20 text
20:10:1 text
20:10:20 text
21:10:19 text
22:10:1 text


with open ("1.txt") as f:
         unsolved = (f.read (). split ())
         sor = sorted(unsolved)
for unsolved_elem in sor:

the problem is that it gives the result in the wrong order

enter image description here

Can someone help me with this? thanks to all for your help

CodePudding user response：

Problem is that you compare strings and it compars char by char using char's code - so it comapars strings "20" and "2:", not integer values 20 and 2 - and char "0" is before char ":" because "0" has code 48 and ":" has code 58.

You have to first split string "1:10:20 text" to tuple/list of strings ("1", "10", "20", "text") and later convert numbers to integers (1, 10, 20, "text") - and it will sort it correctly.

I use io to create file in memory - so everyone can simply copy and test it - but you should use open()

data = '''20:10:20 text
2:10:20 text
1:10:20 text
22:10:1 text
21:10:19 text
20:10:1 text'''

import io

# --- create tuples ---

rows = []

#with open('11000.txt', 'r', encoding='ISO-8859-1') as r:
with io.StringIO(data) as r:    
    for line in r:
        line = line.strip()  # remove `\n` at the end
        numbers, text = line.split(' ')  # split 
        numbers = numbers.split(':')     # split numbers

        rows.append( [int(numbers[0]),int(numbers[1]),int(numbers[2]), line] )

# --- sorting ---

for row in sorted(rows):
   print(row[-1])