Regex split the string at \n but skip the first one if it is \n\n-CodePudding

I want to split some strings on Python by separating at \n and use them in that format, but some of those strings have unexpected newlines and I want to ignore them.

TO CLARIFY: Both examples have only one string.

For example this is a regular string with no unexpected newlines:

Step 1
Cut peppers into strips.
Step 2
Heat a non-stick skillet over medium-high heat. Add peppers and cook on stove top for about 5 minutes.
Step 3
Toast the wheat bread and then spread hummus, flax seeds, and spinach on top
Step 4
Lastly add the peppers. Enjoy!

but some of them are like this:

Step 1
Using a fork, mash up the tuna really well until the consistency is even.

Step 2
Mix in the avocado until smooth.

Step 3
Add salt and pepper to taste. Enjoy!

I have to say I am new at regex and if the solution is obvious, please forgive

Edit: Here is my regex

    stepOrder = []
    # STEPS
    txtSteps = re.split("\n",directions.text)
    listOfLists = [[] for i in range(len(txtSteps)) if i % 2 == 0]
    for i in range(len(listOfLists)):
        listOfLists[i] = [txtSteps[i*2],txtSteps[i*2 1]]
    recipe["steps"] = listOfLists
    print(listOfLists)

directions.text is every one of these examples I gave. I can share what it is too, but I think it's irrelevant.

CodePudding user response：

f = open("your_file_name")
content = f.read()
f.close()

for line in content.split("\n"):
    if re.match("^&",line):
        continue
    print(line)

CodePudding user response：

You can solve this problem by splitting on the following regex:

(?<=\d\n).*

Basically it will get any character in the same line .* which is preceeded by one digit \d and one new line character \n.

Check the regex demo here.

Your whole Python snippet then becomes simplified as follows:

stepOrder = []
# STEPS
recipe["steps"] = re.findall("(?<=\d\n).*", directions.text)