Error while sorting list in lambda mode which works fine in if else statement-CodePudding

Only asc is running and if any other number is added it gives error. Code is given below

    ```y=input("Write 'asc','dec', 'none'")
       converter=lambda x:sorted (x) if y=="asc" else (sorted(x,reverse="True" if y=="dec" else y))
       print (converter (x=[1,2,4,6,10,0, 8, 5]))```

CodePudding user response：

This is because the reverse argument requires a boolean, not a string (True or False, not "True", because "True" is a string).

from w3school tutorial:

reverse=True will sort the list descending. Default is reverse=False

So it should be:

y=input("Write 'asc','dec', 'none'")
converter=lambda x:sorted(x, reverse=y=="dec") if y != "none" else x
print (converter (x=[1,2,4,6,10,0, 8, 5]))

edit: Alexander's answer assumes that you expect "none" and "asc" to work in the exact same way (sort in ascending order), I assume that you want to return the original list without sorting when "none" is passed, it is not clear which is your expectation according to the question

CodePudding user response：

You are using the wrong value for the reverse argument in your second sorting function. The value must be True or False.

I can confirm that this works as expected.

y=input("Write 'asc','dec', 'none'")
converter=lambda x:sorted (x) if y=="asc" else (sorted(x,reverse=True if y=="dec" else False))
print (converter (x=[1,2,4,6,10,0, 8, 5]))

However your code is doing the same thing as this code which is much easier to understand:

print(sorted([1,2,4,6,10,0,8,5], reverse=input()=="desc"))