Django custom model save() method for a non-persisted attribute-CodePudding

In Django 4 custom model save() method, how do you pass a form non-persistent form value?

For example:

The model form below has the non-persistent field called client_secret.

class ClientModelForm(forms.ModelForm):
    client_secret = forms.CharField(initial=generate_urlsafe_uuid)

This field will never be saved, it is auto-generated and will be required to make a hash for a persisted field in my model save() method.

class Client(models.Model):
    client_hash = models.BinaryField(editable=False, blank=True, null=True)

    def save(self, *args, **kwargs):
        """ Save override to hash the client secret on creation. """
        if self._state.adding:
            "GET THE CLIENT SECRET FROM THE FORM"
            client_hash = make_hash_key(client_secret)
            self.client_hash = client_hash

How do I get the client secret value from the form above code example? Is this the most appropriate approach?

CodePudding user response：

You would need to call the super class' save method at the end like so:

super(Client, self).save(*args, **kwargs)

For saving the form, you would need to add a model to the modelform's Meta class, and you would need to add the following logic into a view:

form = Form(request.METHOD)
if form.is_valid():
    uuid = form.instance.client_secret
    form.save()

Where form would look like:

class ClientForm(forms.ModelForm):
    fields...
    class Meta:
        model = ClientModel

Highly recommend taking a look at the docs

Edit

To get the logic into the model save, you could pass it into the kwargs of the save, save(client_secret=client_secret), and then in the save method you could try:

self.field = kwargs.get('client_secret')

then when saving the form, as shown above, you could do

save(client_secret=uuid)