how to stop printing else in if-CodePudding

var1=20

if var1>18:
    print("you can drive")

if var1==18:
    print("you can too drive")

if var1 > 30:
    print("your age is more")

else:
    print("you cannot drive ")

CodePudding user response：

You likely meant to use some elifs. As it stands, let's add some breaks to show how your code looks to the interpreter: three separate conditional statements rather than one.

var1 = 20

if var1 > 18:
    print("you can drive")

###################################

if var1 == 18:
    print("you can too drive")

###################################

if var1 > 30:
    print("your age is more")

else:
    print("you cannot drive ")

If var1 is less than or equal to 30, "your cannot drive" will print.

You want:

var1 = 20

if var1 > 18:
    print("you can drive")
elif var1 == 18:
    print("you can too drive")
elif var1 > 30:
    print("your age is more")
else:
    print("you cannot drive ")

Now it's all one statement.

CodePudding user response：

As per your comment, if you only want to use if and not elif, then this might be a solution:

var1=20
if var1>18:
    if var1>30:
        print("your age is more")
    else:
        print("you can drive")
if var1==18:
    print("you can drive too")
if var1<18:
    print("you cannot drive ")

Result:

input: 20
you can drive
input: 31
your age is more

CodePudding user response：

After correcting the syntax errors, you are getting two outputs because the else is considered for the last if condition, not the first one. I think what you want to implement though looks like this:

var1=20

if var1>18: print("you can drive")

elif var1==18: print("you can too drive")

elif var1 > 30: print("your age is more")

else: print("you cannot drive ")