in Vb.net how to get the number after decimal places.
I tried below code.
Dim number As Decimal = 143.500
Dim wholePart As Integer = Decimal.Truncate(number)
Dim fractionPart As Decimal = number - wholePart
Dim secondPart3 As Integer
secondPart3 = Replace(fractionPart, "0.", "0")
then the result is coming 500, but when i tried 143.050 its giving 50 it should show 050
Thanks
CodePudding user response:
Thanks everyone. i got it with sample below code
Dim numar As Double
If Double.TryParse(TextBox1.Text, numar) Then
Dim rmndr As Double
rmndr = numar Mod 1
If rmndr = 0 Then
Else
TextBox2.Text = Split(CStr(TextBox1.Text), ".")(1)
End If
End If
CodePudding user response:
Your solution (here) is unnecessarily complex. You were on the right track in your original post, but conflated numeric values with formatted string values. Because while 050 are 50 are the same numeric value, when you implicitly call ToString on the value (or explicitly with the wrong formatting) then you would always get 50 because the prefixing 0 is unnecessary when working with numeric values.
What you should do is:
- Get the integral digits of the decimal value
- Convert the underlying decimal value to a String
- (optionally) Format the String specifying the level of precision
- Drop the integral digits off converted string
Here is an example:
Private Function GetFractionalDigits(value As Decimal) As String
Dim integralDigits = Decimal.Truncate(value)
Return value.ToString().Remove(0, integralDigits.ToString().Length 1)
End Function
Private Function GetFractionalDigits(value As Decimal, precisionSpecifier As Integer) As String
If (precisionSpecifier < 0) Then
Throw New ArgumentOutOfRangeException("precisionSpecifier", "precisionSpecifier cannot be less than 0")
End If
Dim integralDigits = Decimal.Truncate(value)
Return value.ToString("N" & precisionSpecifier).Remove(0, integralDigits.ToString().Length 1)
End Function
Fiddle: https://dotnetfiddle.net/SBOXG0