How to make a condition where the row will stop making new lines when the column reach its limit value?

Expected output:

Enter a number: 23

1   
2 3 
4 5 6
7 8 9 10
11 12 13 14 15
16 17 18 19 20 21   
22 23

My code:

#include <stdio.h>

int main(){
    int n;
    int count=1;

    printf("Enter a number: ");
    scanf("%d", &n );

    /*how to find the relation between row and count? when count reach its limit the row must stop executing the new line.*/
    for(int i=1 ; i<= ?? ; i  )
    {
        for(int j = 1; j<=i; j  )
        {
            if(count<=n)
            printf("%d",count  );
        }       
            
        printf("\n");
    }

    return 0;
}       

CodePudding user response：

c

void task() {
    unsigned int n(0);
    unsigned int row(1);

    std::cout << "Enter a number: ";
    std::cin >> n;

    for (int i = 1, buf = 1; i <= n;   i,   buf) {
        std::cout << i;
        if (buf == row) {
            std::cout << std::endl;
              row;
            buf = 0;
        }
    }
}

Output:

Enter a number: 50
1
23
456
78910
1112131415
161718192021
22232425262728
2930313233343536
373839404142434445
4647484950 

CodePudding user response：

See this:

You can easily understand:

 for(int i=1;i<=50;i  ){
       System.out.print(i " "); //for printing number on the same line
    }

//your output will be
//1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50