Such as topic, how to declare the UNION in vb data structure

CodePudding user response:

Structural prototype

 
Typedef struct {
Int dDev; 
Int dPort; 
Int dBaud; 
Int dbeep; 
The union {
Int served1; 
Struct {
Int served2; 
Byte served2_2 [24]. 
Byte served2_3 [3076]. 
}; 
}; 
} LtReader, * PLtReader; 

CodePudding user response:

For each great god to give directions

CodePudding user response:

First of all is not,
Secondly you this union is really boring, served1 and served2 identical, directly on {int, byte [24], byte [3076]} structure definition of good, to what the union,

CodePudding user response:

reference Tiger_Zhao reply: 3/f

is not first,
Secondly you this union is really boring, served1 and served2 identical, directly on {int, byte [24], byte [3076]} of the structure is defined, to what the union,

This is an interface of others, he the inside of the interface structure is as follows

CodePudding user response:

I mean, when you turn into a VB according to the way of no union, pay attention to the place called served1 and served2 became members of the same,

CodePudding user response:

Parts of the union, respectively defined as two types, to which one to use, define which type, with CopyMemory API directly copied from another type,