RegEx for the string at the beginning of which there may be a version-CodePudding

So, my program can accept strings like:

v00240004 Lorem ipsum dolor sit amet, consectetur adipiscing elit.
v0345 Duis nec eleifend nulla..

and also a string without a version number:

Vivamus blandit et nibh nec placerat.
In hac habitasse platea dictumst. Suspendisse potenti.

I tried to write a regular expression to remove the version from the string. And it came out something like this: /^.*?\s/. It finds a match for the version and successfully replaces it with an empty string. But the problem is that it also works on strings without a version. That is, it removes the first word before the space.

So, my question is, how do I write a regular expression that works only on sentences starting with the letter "v" followed by numbers and replaces the version before the first space?

Example: A program receives 2 strings. The first v0255 Example1 string1 and the second Example2 string2. The result after the regular expression should be Example1 string1 and Example2 string2.

CodePudding user response：

This regex is going to help you match only those strings which have first word before space as 'v' then version number.

/^v\d.*?\s/gm

CodePudding user response：

Use the following regex:

^v.*?\s

See regex proof.