How do I make the operator work in the equation to make ans?-CodePudding

Image of current code

Currently if I test by printing 'ans', it just prints it as a character like ' ' which doesn't work with the equation for 'ans', how do I change this so it adds? what 'ans' prints as

I'm very new to coding so this may seem like an obvious question- sorry!

CodePudding user response：

the right answer for your case is probably to use branching if else

ans = (5,' ',6)
if ans[1] == ' ':
   print(ans[0]   ans[2])
elif ans[1] == "/":
   print(ans[0] / ans[2]) 
# etc.

you could possibly get away with ast.literal_eval

import ast
ans = (6,'-',2)
eqn = f"{ans[0]} {ans[1]} {ans[2]}"
print("EQN:",eqn,"=",ast.literal_eval(eqn))

the most correct answer however is probably to use a dictionary mapping to deliberately expose specific programmer defined operators

import operator
# the function to call for a given operator
operators = {" ":operator.add,
             '-':operator.sub}
ans = (6,'-',2)
operators[ans[1]](ans[0],ans[2])

CodePudding user response：

Change definition of ans to :

ans = eval(str(n1)   ops   str(n2))

This makes a string of operands and operator stitched together. And then calls eval() function in python which evaluates arithmetic operations denoted by string.

CodePudding user response：

You can do it like this :


def sum(num1,num2):
    print(int(num1) int(num2))



operations = {" ":sum}

operator = input("Enter :").split()

operations.get(operator[1])(operator[0],operator[2])

There are many ways to do it or to solve your problem.