how to set dictionary if select key is repeats with python?-CodePudding

I'm using python 3 and I have a dictionary containing some scheduler data. Now i want to set that if a day name repeats in the data list.

here is the case and code :

data = [
    {'day': 'Monday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
    {'day': 'Tuesday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
    {'day': 'Wednesday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
    {'day': 'Thursday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
    {'day': 'Friday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
    {'day': 'Saturday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
    {'day': 'Saturday', 'full_day': False, 'close_day': True, 'start_time': None, 'close_time': None},
    {'day': 'Sunday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None}
]

as you can see Saturday is 2 times in data list. second one is full day false and close day true . Now i want that to stay there and first one Saturday object remove from the list. And this thing with all days which comes in list multiple times.

CodePudding user response：

You can use a dictionary with day as the key for this (using dictionary comprehension):

data = list({d['day']: d for d in data}.values())

This will keep only the last occurrence of each day.

The above is equivalent to:

'''
data_dict will be:
{
   'Monday': {'day': 'Monday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
   'Tuesday': {'day': 'Tuesday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
   ...
}
'''
data_dict = {}

for d in data:
    data_dict[d['day']] = d

data = list(data.values())

data_dict is a dictionary of day:data. So for each day, data_dict will store its latest entry from data (as older entries will be overridden).

CodePudding user response：

for-loop will find a saturday you don't need and pop it

data = [
{ 'day': 'Monday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
{ 'day': 'Tuesday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
{ 'day': 'Wednesday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
{ 'day': 'Thursday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
{ 'day': 'Friday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
{'day': 'Saturday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None},
{ 'day': 'Saturday', 'full_day': False, 'close_day': True, 'start_time': None, 'close_time': None},
{'day': 'Sunday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None} 
]

for e,i in enumerate(data):
    if i['day'] == 'Saturday' and i['full_day']:
        data.pop(e)

for i in data:
    print(i)

# {'day': 'Monday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None}
# {'day': 'Tuesday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None}
# {'day': 'Wednesday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None}
# {'day': 'Thursday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None}
# {'day': 'Friday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None}
# {'day': 'Saturday', 'full_day': False, 'close_day': True, 'start_time': None, 'close_time': None}
# {'day': 'Sunday', 'full_day': True, 'close_day': False, 'start_time': None, 'close_time': None}