For (int k=1; k<=nodesCount; + + k) {
For (int I=1; i<=nodesCount; + + I) {
If (short [I] [k].={NOT_CONNECTED)
For (int j=1; j<=nodesCount; + + j) {
If (short [k] [j].=NOT_CONNECTED & amp; & (short [I] [j]==NOT_CONNECTED | | short [I] [k] + short [k] [j]
Short [I] [j]=short [I] [k] + short [k] [j];
}
}
}
}
}
CodePudding user response:
Seemingly for there are data dependent on how the parallel
CodePudding user response: