Writing a sequence of numbers like: 1 22 333 4444 55555 via recursion c-CodePudding

I have to write a code in c , which would display a monotonic sequence of numbers like 1 22 333 to the number I input, so number k is repeating k times. It's like i input 6, the code would display 1 22 333 4444 55555 666666. It has to be via recursion.

For now, if i cin >> 15 output is a row of numbers from 1 to 15. I have a feeling this is extremely easy but nothing crosses my mind right now. This is my attemp:

#include <iostream>

using namespace std;

int x;

void func(int n) 
{
    if(n>=1){
        func(n-1);
        std::cout<< n << " ";
    }   
}

int main()
{
    cout << "Enter a natural number: ";
    cin >> x;
    func(x);
}

CodePudding user response：

There you go:

#include <iostream>

int x{0};

void func(int n) 
{
    if(n>=1){
        func(n-1);
        for (int i = 0; i != n;   i)
            std::cout << n;
        std::cout << " ";
    }   
}

int main()
{
    std::cout << "Enter a natural number: ";
    std::cin >> x;
    func(x);
}

CodePudding user response：

If you want a recursive solution add a 2nd variable so n will always have the original, and m will always have the modified value


using namespace std;

int x;

void func(int n,int m) 
{
    if(m>=1){
        func(n,m-1);
        std::cout<< n << " ";
    }   
}

int main()
{
    cout << "Enter a natural number: ";
    cin >> x;
    func(x,x);
}