limit = int(input("Limit: "))
allvalue = ""
count = 0
number = 0
while count < limit:
number = 1
count = number
allvalue = str(number) " "
print(allvalue)
This is my output 1 2 3 4 5 6 7 8 9
I want the symbol only in between the numbers.Not to be in the last or the first.
CodePudding user response:
A likely solution is using " ".join()
, which uses the string method on the " "
to collect the values together
>>> values = "1 2 3 4 5".split()
>>> " ".join(values)
'1 2 3 4 5'
CodePudding user response:
limit = int(input("Limit: "))
allvalue = ""
count = 0
number = 0
while count < limit:
number = 1
count = number
if count != limit:
allvalue = str(number) " "
else:
allvalue = str(number)
print(allvalue)
Hope this help.
CodePudding user response:
I would like to share with you a sure shot mathematical solution to this problem.
This problem is a typical variation of
Sum of n numbers
problem, where thesum
depictinglimit
here is already given as input, instead ofn
.
import math
limit = int(input("Limit: ")) # n * (n 1) / 2 >= limit
n = math.ceil( ((1 4*2*limit)**0.5 - 1) / 2 ) # ((b^2 - 4ac)^(1/2) - b) / 2a where a = b = 1, c = 2*limit
allValue = " ".join([str(i) for i in range(1, n 1)])
print(allValue)
CodePudding user response:
You don't need both the number
and count
variables, and by starting from initial value you can add the
before the number.
limit = int(input("Limit: "))
count = 1
allvalue = str(count)
while count < limit:
count = 1
allvalue = " " str(count)
print(allvalue)
CodePudding user response:
You could also try using a for loop.
limit = int(input("Limit: "))
allvalue = ""
for i in range(0, limit):
if i 1 == limit:
allvalue = str(i 1)
else:
allvalue = str(i 1) " "
print(allvalue)
CodePudding user response:
Here is simple and easy approach, you can try slice in the result string
print(allvalue[:-2])
code:
limit = int(input("Limit: "))
allvalue = ""
count = 0
number = 0
while count < limit:
number = 1
count = number
allvalue = str(number) " "
print(allvalue)
print(allvalue[:-2])
output: result shared : https://onlinegdb.com/HFC2Hv4wq
Limit: 9
1 2 3 4
1 2 3 4