Given an array of strings, return another array containing all of its longest strings. using Dart-CodePudding

Given an array of strings, return another array containing all of its longest strings.

Example

For inputArray = ["aba", "aa", "ad", "vcd", "aba"], the output should be solution(inputArray) = ["aba", "vcd", "aba"].

[execution time limit] 4 seconds (dart)

[input] array.string inputArray

A non-empty array.

Guaranteed constraints: 1 ≤ inputArray.length ≤ 10, 1 ≤ inputArray[i].length ≤ 10.

[output] array.string

Array of the longest strings, stored in the same order as in the inputArray.

I know that the javascript code answer of the above question but did't know how to write it into dart. this is the javascript //

  var maxLength = Math.max(...inputArray.map(s => s.length));
    return inputArray.filter(s => s.length === maxLength);

CodePudding user response：

You can sort the list by its item's length and then search for items that have equal length to the longest item in sorted list. like this:

var inputArray = ["aba", "aa", "ad", "vcd", "aba"];
inputArray.sort(
  (a, b) => b.length.compareTo(a.length),
);
var result = inputArray
    .where((element) => element.length == inputArray.first.length)
    .toList();
print("inputArray = $result"); //[aba, vcd, aba]

CodePudding user response：

This is pretty easy.

final inputArray = ["aba", "aa", "ad", "vcd", "aba"];
inputArray.map((e) => e.length).toList().sort();
inputArray.retainWhere((el) => el.length == inputArray.first.length);

log(inputArray.toString()); // [aba, vcd, aba]

Output:

[aba, vcd, aba]