Multiple inputs in one line in C-CodePudding

I've newly started learning C and am stuck with this problem. I need to insert a (user inputted) number of elements in a single line with space separation. If the number of elements was known, I could just write cin >> var1 >> var2 >> ... >> varN;. But how do I do it with any number of elements (loop maybe)?

This is what I'm trying to do:

#include<bits/stdc  .h>
using namespace std;

int main() {
    int n;
    cin >> n;
    int arr[n];
    for (int i=0; i<n; i  ) {
        //stuck here
    }
}

I could have written cin >> arr[i]; and proceeded, but that would require the user to press enter after every input, which I cannot do due to the question's restrictions. How do I write the code so that all my input for array elements can be given in a single line?

PS: I've seen several similar questions already answered on the site, but most of them involve implementations using vectors or are beyond my current level of understanding. A simpler solution will be appreciated.

CodePudding user response：

cin>>arr[i] does not require the user to press enter after every input. You just need to give whitespace between the integer inputs. It will scan the array normally.

CodePudding user response：

You would probably want to replace your array with a std::vector to make it resizable in run time. If you do like in your example the program will not compile because n is not known when the program is built.

Here is a simple example

#include <iostream>
#include <vector>
#include <string>

using namespace std;

int main() {
    int n = 0;
    cin >> n;
    vector<string> arr; // A vector (ie kind of a variable sized array)
    for (int i=0; i<n; i  ) {
        string str;
        cin >> str; // Read a word
        arr.push_back(str); // Add a string to the vector
    }

    // To use the data
    for (int i = 0; i < arr.size();   i) {
        cout << arr.at(i) << "\n"; // Print value of vector
    }
    // or like this
    for (auto str: arr) {
        cout << str << "\n";
    }
}