Here is a code for dynamic memory allocation using malloc

void main()
{
    int *p,n=5;
    p=(int*)malloc(5*sizeof(int));

    p[0]=10;
    //  or *p=10;
    p[1]=20
    //  or *(p 1)=20;
}

As per my knowledge, p is a pointer variable that points to the base address of the allocated memory. If I dont use the * operator, then I can't access the contents pointed to by p. But the statements p[1]=20 and *(p 1)=20 do work the same. Why is this same and also what is the use of * if we can do it this way too p[1] But then does it also means that when i use malloc the array allocated to the process will have the same name as the pointer used to point the base address

CodePudding user response：

The difference between *p and p[1] is that *p is a pointer that points to the first element of the array, while p[1] is the second element of the array. The difference is that *p gives you access to the entire array, while p[1] only gives you access to the single element.