This is what I am trying to do:

the user needs to enter 4 numbers (already done)
then I want to calculate the average of those 4 digits but The first digit needs to counts 1x, the second digit 2x, the third digit 3x and the fourth digit 4x. (already done)

(this is the part where i am stuck)
Also calculate the highest number. If the highest grade is more than 3 points above the average, the screen will show:

cheater!
-1

If the highest grade is less than 3 points above the average, the actual average will appear on the screen, rounded to 1 decimal place.

public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        int i;
        double sum;
        double number;
        double result = 0;

        for (i = 1; i < 5; i  ) {
            number = sc.nextDouble();
            sum = number * i;
            result  = sum;
            if (number%result > 3) {
                System.out.println("cheater!\n"   "-1.0");

            } else{
                System.out.printf("%3.1f", result / 10);
            }
        }
    }
}

As you can see above here, this is what I got for now. Don't know exactly what I am doing wrong here?

These are my input/results:

5.5
6.1
7.3
5.8

0.6cheater!
-1.0
cheater!
-1.0
cheater!
-1.0

Expected results:

Sample Input 1:

5.5
6.1
7.3
5.8

Sample Output 1:

6.3

Sample Input 2:

3.0
5.4
9.8
2.5

Sample Output 2:

cheater!
-1.0

CodePudding user response：

1. to calculate average you need the sum(sum variable) divide by amount of numbers(4 in your case)
2. you need to use array to find the highest number
3. the if logic is incorrect

I suggest:

public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        double sum;
        double[] number = new double[4];
        double result = 0;
        double highestNum = 0;

        for (int i = 0; i <= 3; i  ) {
            number[i] = sc.nextDouble();
            sum  = number[i] * i;
            if(highestNum<number[i]){
                 highestNum = number[i];
                 }
            }
            double aveNum = sum/4;
               
            if ((highestNum-aveNum)> 3) {
                System.out.println("cheater!\n"   "-1.0");

            } else{
                System.out.printf("%3.1f", result / 10);
            }
        }
    }

CodePudding user response：

        double sum;
        double number;
        double result = 0;
        double max = 0;

        //Compute the sum
        for (int i = 1; i < 5; i  )
        {
            number = sc.nextDouble();
            sum = number * i;
            result  = sum;

            if (max < number)
                max = number;
        }

        //Average
        double average = Math.Round((double)result / 10, 1);

        //Compare to data
        if (max > average   3)
            System.out.println("cheater!\n"   "-1.0");
        else
            System.out.printf("%3.1f", average);