Must be silly but I can't figure out how to ignore/skip percentages in a string, and only capture amounts (any locale).
e.g. 6.000 6.000% 12.24 with regex [.,\d] \d(?! ?%) still matches the middle rate with 6.00.
See https://regex101.com/r/jn7gHD/2
Desired outcome: match 6.000 and 12.24, not 6.000% (or 6.000 % if encountered)
CodePudding user response：
It matches the 6.00 in 6.000% because it's followed by 0, which isn't %.
You can solve this by forcing the match to end at a word boundary.
[.,\d] \d\b(?! ?%)
CodePudding user response：
Alternative regex: Don't match a amount if there's a \s*% at the end:
(?!\d (?:[.,]\d )*\s*%)\d (?:[.,]\d )*