I wonder if anyone got an insights regarding this error I got from postman below:
{
"timestamp": "2022-12-29T07:59:00.313 0000",
"status": 500,
"error": "Internal Server Error",
"message": "could not execute statement; SQL [n/a]; nested exception is org.hibernate.exception.SQLGrammarException: could not execute statement",
"path": "/v1/personal/add"
}
Here is My Controller Class:
PersonalController.java
@PostMapping("/add")
public ResponseEntity <PersonalResponseDto> addPersonalInfo (@RequestBody final PersonalRequestDetailsDto personalRequestDetailsDto){
PersonalResponseDto dto = personalService.addPersonalInformation(personalRequestDetailsDto);
return ResponseEntity.ok(dto);
}
Here is My Service Class:
PersonalService.java
public PersonalResponseDto addPersonalInformation(PersonalRequestDetailsDto personalRequestDetailsDto){
PersonalEntity personalEntity = personalMapper.toEntity(personalRequestDetailsDto);
PersonalEntity saveInfo = personalRepository.save(personalEntity);
return personalMapper.toDto(saveInfo);
}
and here is my Entity class:
@Data
@ComponentScan("personal")
@NoArgsConstructor
@Table(name = "student_personal_information")
@Entity
public class PersonalEntity {
@Id
@GeneratedValue(strategy = GenerationType.SEQUENCE)
@Column(name = "id", nullable = false)
private Long id;
@Column(name = "lastname", columnDefinition = "CLOB")
private String lastname;
@Column(name = "firstname", columnDefinition = "CLOB")
private String firstname;
@Column(name = "middleinitial")
private String middleinitial;
@Column(name = "age")
private Integer age;
@Column(name = "image")
private Byte image;
}
I'd appreciate any help as to why I'm getting the above error in postman.
Thank you.
I wanted to add an information that would store to DB but i'm getting an error.
Here is my Request DTO:
@Data
@NoArgsConstructor
@AllArgsConstructor
public class PersonalRequestDetailsDto implements Serializable {
private static final long serialVersionUID = -7175623352146349491L;
@NotEmpty
private String lastname;
@NotNull
private String firstname;
@NotEmpty
private String middleinitial;
@NotNull
private Integer age;
}
Addendum: Upon the advice of one commenter here, I learned that the main issue herein is my entity under column image.
Here is the error I got:
column "image" is of type bytea but expression is of type smallint Hint: You will need to rewrite or cast the expression.
To ask, what data type exactly should I declare in my entity to address this issue?
CodePudding user response:
Idealy, you should save only path to your image in your database, after you have uploaded the file to a separate image storage.
Make the image type String.
CodePudding user response:
I normally save images as files and save the details in the DB. However if you still want to save it in the DB then you can change as follows:
@Lob
@Column(name = "image")
private byte[] image;