I have a dataframe with a few columns that contain time/ date information. I'm familiar with using lubridate to parse date-time (ie mm/dd/yyyy hh:mm:ss), but this dataframe has date time in reverse order (ie hh:mm:ss mm/dd/yyyy). How do I get this to read as a date/time? The column is currently reading as a character which is useless to me. Below is an example of what my dataset looks like. I can't make the "time_date" column read as a date -time.
df <- tribble(~activity, ~time_date,
"run", "15:06:17 03/08/2016",
"skip", "09:01:00 03/08/2016")
CodePudding user response:
You should first convert it to a date time with right format and after that you can use strftime
with the desired format like this:
datetimes <- as.POSIXct(df$time_date, format = "%H:%M:%S %m/%d/%Y")
df$time_date <- strftime(datetimes, format = "%m/%d/%Y %H:%M:%S")
df
#> # A tibble: 2 × 2
#> activity time_date
#> <chr> <chr>
#> 1 run 03/08/2016 15:06:17
#> 2 skip 03/08/2016 09:01:00
Created on 2023-01-04 with reprex v2.0.2
CodePudding user response:
Using base R
df$time_date <- sub("(\\S )\\s (\\S )", "\\2 \\1", df$time_date)
-output
> df
# A tibble: 2 × 2
activity time_date
<chr> <chr>
1 run 03/08/2016 15:06:17
2 skip 03/08/2016 09:01:00
CodePudding user response:
With dplyr
and lubridate
on character class data.
library(dplyr)
library(lubridate)
df %>%
rowwise() %>%
mutate(dd = strsplit(time_date, " "),
date_time = mdy_hms(paste(unlist(dd)[2], unlist(dd)[1])),
dd = NULL) %>%
ungroup()
# A tibble: 2 × 3
activity time_date date_time
<chr> <chr> <dttm>
1 run 15:06:17 03/08/2016 2016-03-08 15:06:17
2 skip 09:01:00 03/08/2016 2016-03-08 09:01:00