I am trying to make regEx for password. (JavaScript)

[Updated]

Regex Requirements

• must be 6-18 characters consisting of english letter (capital or small), number and special character. (at least one of each)
• must start with a letter.
• the order of letters, numbers and special characters does not matter.
• does not allow Korean letters.

^(?=.*[0-9])(?=.*[-a-zA-Z])(?=.*[`~@#!$%^& =_-]){8,16}.*$

This should not pass the test in the following cases.

1. It has over 16 characters.
2. It contains a korean character.

However, the above mentioned cases are all passed.

Here i am sharing my regex tester link.

https://regexr.com/75qhd

Thanks in advance.!

CodePudding user response：

Try this:

^(?=.{6,18}$)(?=.*\d)(?=.*[`~@#!$%^& =_-])(?=[A-Za-z][A-Za-z\d`~@#!$%^& =_-] $).*$

Edit: The previous regex matches things like asAS12`한글, I added $ after this part [`~@#!$%^& =_-] , to ensure that the string ends with one of the special characters listed in [], thanks to @Wiktor Stribiżew who mentioned this issue.

Explanation

• ^ the start of the line/string.

• (?=.{6,18}$) ensures that the string is 6-18 in long.

• (?=.*\d) ensures that there must be at least one digit.

• (?=.*[`~@#!$%^& =_-]) ensures that there must be at least one special character listed in []

• (?=[A-Za-z][A-Za-z\d`~@#!$%^& =_-] $)

  • [A-Za-z] ensures that the first character is a letter.
  • [A-Za-z\d`~@#!$%^& =_-] $ followed by one or more letters, digits or special characters listed in the [] no matter of the order, followed by the end of the string/line.

• .* if the above requirements are satisfied, then match the whole string.

• $ the end of the line/string.

See regex demo