The regex should invalidate the phone number if all the digits are same. For eg - 0000000,1111111,2222222,etc. should be invalid. But on the other hand if I enter 11111112 then this should be valid as it contains another digit as well. The length of the regex should be between 7 to 15.
I tried with this (?!(\d)\1{6})([0-9]{7,15}) but the same is not working as expected. If there is any better way, please suggest me the same.
CodePudding user response：
You can use a positive lookahead pattern at the beginning to assert that there exists at least a digit whose following digit isn't the same:
^(?=.*(\d)(?=\d)(?!\1))\d{7,15}$
Demo: https://regex101.com/r/tn9kJd/1
CodePudding user response：
You could use a single negative lookahead to rule out the same digits 0-9 as in C# using \d could match more digits than only 0-9:
^(?!([0-9])\1 $)[0-9]{7,15}$
The pattern matches:
^Start of string(?!Negative lookahead, assert that to the right is not([0-9])\1 $Capture a digit 0-9 in group 1 and repeat that same digit using a backreference\1one more times till the end of the string
)Close the lookahead[0-9]{7,15}Match 7-15 digits in the range 0-9$End of string
See a regex101 demo.