I want to validate phone number using regExp-CodePudding

The phone number should start with 0 followed by 6 or 7 and should contain 10 digits only

Here are some sample phone numbers

0754758644 ,0621165600

Here is what I tried

String pattern = r'(^(?:[0]9)?[0-9]{10,12}$)';

CodePudding user response：

this regex should work for you:

String pattern = r'(^0(6|7)\d{8}$)'

I limited the digits to 8, because the 0 and the 6/7 already take up two digits of the length. The {8} only limits the direct predecessor (the digits matcher \d).

find out more about this regex here: regex101

CodePudding user response：

Use this regex pattern -

String pattern = r'([0][6,7]\d{8})

CodePudding user response：

String pattern = r'^(?:[ 0][1-9])?[0-9]{10,12}$';
RegExp regExp = new RegExp(patttern);

regExp.hasMatch(value)

or you can apply keyboardtype property to textfield or textformfield if you are not familiar with regExp