currently I faced issue with python code

I have two questions relate with "def" code.

1) I need to print out 6 alphabet which is "K,E,Y,S,N,O"

slimier like under sample

enter image description here

2) how can I print out this alphabet if user typing one word like "KEY" then print out *mark with KEY or If user typing "BED" then print out "E"only because we only have alphabet with K,E,Y,S,N,O

if can anyone help me with this two questions? I appreciate that

Thanks

CodePudding user response：

Question 1 need work with 2-dimensional list (list with lists for rows) and I skip this problem.

As for Question 2 you can filter chars in word.

You can treat string "BED" as list of chars (even without using list("BED")) and you can use it in for-loop to check every char with list ["K","E","Y","S","N","O"] (or "KEYSNO") and skip chars "B" and "D"

#my_chars = "KEYSNO"  # also works
my_chars = ["K","E","Y","S","N","O"]

word = "BED"

for char in word:
    if char in my_chars:
        print(char, "- OK")
    else:
        print(char, "- unknown")

Result:

B - unknown
E - OK
D - unknown

This way you can create new list to keep only correct chars

my_chars = ["K","E","Y","S","N","O"]

word = "BED"

filtered_chars = []        

for char in word:
    if char in my_chars:
        filtered_chars.append(char)

print(filtered_chars)

Result:

['E']

In Python you can write it even shorter using list comprehension

filtered_chars = [char for char in word if char in my_chars]        

Eventually you can write it with function filter() like

filtered_chars = list(filter(lambda char: char in my_chars, word))