Overview
I want to automatically test all 200 pages of our website every week after the update to see if the update broke any of them
The test case
- Login and go to the sitemap
- Get the URLs and check each for their HTTP status
The code
it('check HTTP status', () => {
cy.visit(Cypress.config('siteMapUrl'))
cy.get('.portlet-separator').should('contain', 'Available Links')
cy.get('.inputwrapper>a')
.each(($el, index, $list) => {
if($list){
cy.get($el)
.invoke('attr', 'href')
.then(href => {
cy.request(Cypress.config('url') href)
.should('have.property', 'status', 200)
})
}
})
What happens:
Once an URL returns anything else than status 200 the test fails.
What I would like:
I would like Cypress to iterate through the complete list of URLs before returning the URLs that failed.
Why?
If more than one URL in the list is broken, I will not find the 2nd broken URL with this test until our devs have fixed the first one. Yet I need to produce a list with all broken URLs at the beginning of the week
I have already seen this answer but I would like to know if there is a different solution before I try to implement this
CodePudding user response:
You should not use .should()
after each URL - that will fail immediately, even if setting failOnStatus: false
.
Instead save the results and check at the end.
const failed = []
cy.get(".inputwrapper>a").each(($el, index, $list) => {
cy.get($el)
.invoke("attr", "href")
.then((href) => {
cy.request({
url: Cypress.config("url") href,
failOnStatusCode: false,
})
.its('status')
.then(status => {
if (status !== 200) {
failed.push(href)
}
})
})
}
})
.then(() => {
// check inside then to ensure loop has finished
cy.log(`Failed links: `${failed.join(', ')`)
expect(failed.length).to.eq(0)
})