How do I turn this list into a string?-CodePudding

I'm trying to convert binary to decimal to ASCII. Using this code, I'm able to take a binary input and split it into chunks of 7 bits.

def binary_to_ascii7bits(bstring):
    n = 7
    byte = [bstring[i:i n] for i in range(0, len(bstring), n)]
    print(byte)

I need to be able to turn each 7-bit substring into a decimal number in order to use the chr function. If I try to turn this list into a string, it prints for example, "['1111000']", but I cannot have the brackets and apostrophes in the string. What can I do to fix this?

CodePudding user response：

First of all, for the chr function it should be an integer, not a decimal.

Add this list comprehension before the print function -

byte = [chr(64   int(i)) for i in byte]

This will give the string for the bytes. I think this is what you want.

CodePudding user response：

You can add just one more line (as below) to achieve what you described.

You have int(..., 2) to convert the string representation of a binary number into an integer. Then apply chr to get a character. This procedure is done using (list) comprehension, so that the result is a list of characters. Then use join to make a single string.

text = '1111000' * 10

def binary_to_ascii7bits(bstring):
    n = 7
    byte = [bstring[i:i n] for i in range(0, len(bstring), n)]
    return ''.join(chr(int(x, 2)) for x in byte)

print(binary_to_ascii7bits(text)) # xxxxxxxxxx