I have this array [-1, 8, -1, 6, -1, 4, -1, 2, 0, -1]
I want to rearrange in place using the loop, where the element will place in its index
For example, element 8 will be placed in the 8th index, element 0 will be in the 0th index
output [0,-1,2,-1,4,-1,6,-1,8,-1]
;
This is my code
let arr = [-1, 8, -1, 6, -1, 4, -1, 2, 0, -1];
for (let i = 0; i < arr.length; i ) {
const elem = arr[i];
// console.log('---',elem)
if (i !== arr[i]) {
if (arr[i] !== -1) {
const valInd = arr[arr[i]];
arr[arr[i]] = elem;
arr[i] = valInd
}
}
};
console.log(arr);
Please help me understand where I am missing
CodePudding user response:
You forgot to sort an array. First sort it and then use your logic
let arr = [-1, 8, -1, 6, -1, 4, -1, 2, 0, -1];
arr.sort()
for (let i = 0; i < arr.length; i ) {
const elem = arr[i];
// console.log('---',elem)
if (i !== arr[i]) {
if (arr[i] !== -1) {
const valInd = arr[arr[i]];
arr[arr[i]] = elem;
arr[i] = valInd
}
}
};
console.log(arr);
CodePudding user response:
let arr = [-1, 8, -1, 6, -1, 4, -1, 2, 0, -1];
let output = new Array(arr.length).fill(-1);
arr.forEach(el => {
if(el === -1) return;
output[el]= el;
});
console.log(output);
CodePudding user response:
I think this code will help you, if you want only run for this items.
let arr = [-1, 8, -1, 6, -1, 4, -1, 2, 0, -1];
for (let i = 0; i < arr.length; i ) {
if (arr.includes(i)) {
const ind = arr.indexOf(i);
arr[ind] = arr[i];
arr[i] = i;
}
}
console.log(arr);