Hai i want to ask about my problem. So i have a several function to get data from database. And for that i have a connection database. My several function located in one file function. And when i run the code i have a message notification like this.
And this is for my function code
function getDataToko()
{
$db = getDBConnection();
$query = "SELECT * FROM master_toko WHERE status_ot='1' ORDER BY nama_ot DESC";
$result = mysqli_query($db, $query);
mysqli_close($db);
return $result;
}
function getDataAkses()
{
$db = getDBConnection();
$query = "SELECT tk.nama_ot, ha. * FROM master_toko AS tk, master_hak_akses AS ha WHERE tk.id_ot = ha.id_ot AND ha.status_ha = '1'";
$result = mysqli_query($db, $query);
mysqli_close($db);
return $result;
}
And this for the page html i called the function
<select class="form-control select2bs4" name="namaToko" required>
<option disabled="disabled" selected="selected">Pilih Toko</option>
<?php $toko = getDataToko(); ?>
<?php
while ($dataToko = mysqli_fetch_array($toko)) {
?>
<option value="<?= $dataToko['id_ot'] ?>">
<?= $dataToko['nama_ot'] ?>
</option>
<?php
}
?>
</select>
<tbody>
<?php
$n = 1;
$akses = getDataAkses();
while ($dataAkses = mysqli_fetch_array($akses)) {
if ($dataAkses['status_ha'] == 1) {
$status = "Aktif";
$idStatus = "1";
}
if ($dataAkses['status_ha'] == 2) {
$status = "Tidak Aktif";
$idStatus = "2";
}
?>
<tr data-row-id="<?= $dataAkses['id_ha'] ?>">
<td>
<?php echo $n ; ?>
</td>
<td>
<?php echo $dataAkses['id_ha'] ?>
</td>
<td>
<?php echo $dataAkses['nama_ot'] ?>
</td>
<td>
<?php echo $dataAkses['nama_ha'] ?>
</td>
<td>
<?php echo $status ?>
</td>
<td>
<button type="button" class="view-detail btn btn-success" data-id="<?= $dataToko['id_ot'] ?>"> Edit </button>
<!-- <button onclick="document.getElementById('delete').style.display='block'" class="view-delete btn btn-danger">Delete</button> -->
<button type="button" class="view-delete btn btn-danger" data-id="<?= $dataToko['id_ot'] ?>" id="deleteButton"> Delete </button>
<?php
include 'hapus_toko.php';
?>
</td>
</tr>
<?php
include 'edit_toko.php';
}
?>
</tbody>
This my config.php
<?php
function getDBConnection() {
define('DB_SERVER', 'localhost');
define('DB_USERNAME', 'root');
define('DB_PASSWORD', '');
define('DB_DATABASE', 'dbcity');
$db=mysqli_connect(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_DATABASE);
if(!$db) {
die("<script>alert('Gagal tersambung dengan database.')</script>");
}
return $db;
}
?>
Can anyone help me for this bug?
CodePudding user response:
This is happening because your define
is inside getDBConnection
, which you call more than once. You need to move the definitions outside the function at the top of config.php