Split array of strings into a matrix of numeric digits-CodePudding

I want to convert n integers to base b, and write every digit as a single number in a matrix.

I get the base b representation with:

stringBaseB=dec2base(0:1:1000,b,10)

but don't know how to split every string into a single char

[[0,0,0,0];[0,0,0,1];[0,0,0,2];...]

I can use array2table to split the individual characters:

tableBaseB=array2table(dec2base(stringBaseB,b,10))

but that's not a numeric matrix. Also, in base b>10 I get alphanumeric characters, which I need to convert to numeric by an equivalence like

alphanumeric=["1","A","c","3"]
numericEquivalence=[1,1 i,-3,0]

There is a vectorized way to do it?

CodePudding user response：

For some base b < 11, where the character array from dec2base is always going to be single-digit numeric characters, you can simply do

b = arrayfun( @str2double, stringBaseB );

For some generic base b, you can make a map between the characters and the values (your numericEquivalence)

charMap = containers.Map( {'1','2','3'}, {1,2,3} );

Then you can use arrayfun (not strictly "vectorized" as you requested but it's unclear why that's a requirement)

stringBaseB=dec2base(0:1:1000,b,10);
b = arrayfun( @(x)charMap(x), stringBaseB );

This gives you a numeric output array, for example stringBaseB=dec2base(0:5,3,10) gives

stringBaseB =
  6×10 char array
    '0000000000'
    '0000000001'
    '0000000002'
    '0000000010'
    '0000000011'
    '0000000012'

b =
  6x10 double array
     0     0     0     0     0     0     0     0     0     0
     0     0     0     0     0     0     0     0     0     1
     0     0     0     0     0     0     0     0     0     2
     0     0     0     0     0     0     0     0     1     0
     0     0     0     0     0     0     0     0     1     1
     0     0     0     0     0     0     0     0     1     2