I want add a random letter after each N-th letter. Which is the best way to achieve this?

Example: I have string like this: aaaaaaaaaaaaaaaaa, and i want to get this: aaamaaaeaaa4aaamaaalaa

CodePudding user response：

You can try the below code:

public class Test {
    public static void main(String[] args) {
        String originalString = "aaaaaaaaaaaaaaaaa";
        int skipcharactorCount = 3;
        StringBuilder stringBuilder = new StringBuilder();
        stringBuilder.append(originalString.charAt(0));
        for (int i = 1; i < originalString.length(); i  ) {
            if (i%skipcharactorCount==0){
                stringBuilder.append(getRandomChar());
            }
            stringBuilder.append(originalString.charAt(i));
        }
        System.out.println(stringBuilder.toString());
    }

    private static char getRandomChar() {
        return (char) ((int) (Math.random() * 1000) % 26   97);
    }
}

Here I am converting a random number to a lowercase character

CodePudding user response：

This would be one solution:

    public String addRandomLetter(int chunkSize, String str)
    {
        String[] arr = str.split("(?<=\\G.{"   chunkSize "})"); // Split the string into chunks of size chunkSize
        Random r = new Random();

        // Add for each chunk a random character at the end
        for (int i = 0; i < arr.length; i  )
        {
            char c = (char)(r.nextInt(26)   'a');
            arr[i]  = c;
        }

        return String.join("", arr); // Join the chunks into one big string.
    }

CodePudding user response：

There are heaps of ways you could do this. You could make a Python script. Use a for loop:

import random
import string

for x in range(totalLetters):
    if(x % n == 0):
       print(random.choice(string.ascii_letters))
    else:
        print("some letter")

The so the for loop basically counts from 1 to totalLetters. Then the if statement checks if n letters has passed. It's just a base and you can go from there.