Python list append only dictionary-CodePudding

I have a 2 dictionaries and it contains data like this:


item1 = {'data': [{'a': 11, 'b': 22}, {'c': 33, 'd': 44}]}

item2 = {'data': [{'e': 55, 'f': 66}, {'g': 77, 'h': 88}]}

I wanted to append only item1['data'] and item2['data'] into the single list, how can I append this?. My expected list is

[{'a': 11, 'b': 22}, {'c': 33, 'd': 44}, {'e': 55, 'f': 66}, {'g': 77, 'h': 88}]

CodePudding user response：

You can unpack the list.

>>> item1 = {'data': [{'a': 11, 'b': 22}, {'c': 33, 'd': 44}]}
>>> item2 = {'data': [{'e': 55, 'f': 66}, {'g': 77, 'h': 88}]}
>>>
>>> [*item1['data'], *item2['data']]
[{'a': 11, 'b': 22}, {'c': 33, 'd': 44}, {'e': 55, 'f': 66}, {'g': 77, 'h': 88}]

Or, you can use list.extend method.

>>> result = item1['data'].copy()
>>> result
[{'a': 11, 'b': 22}, {'c': 33, 'd': 44}]
>>> result.extend(item2['data'])
>>> result
[{'a': 11, 'b': 22}, {'c': 33, 'd': 44}, {'e': 55, 'f': 66}, {'g': 77, 'h': 88}]

CodePudding user response：

2 of the multiple ways:

item1 = {'data': [{'a': 11, 'b': 22}, {'c': 33, 'd': 44}]}

item2 = {'data': [{'e': 55, 'f': 66}, {'g': 77, 'h': 88}]}
outlist = item1['data'] item2['data']
print (outlist)

item1 = {'data': [{'a': 11, 'b': 22}, {'c': 33, 'd': 44}]}

item2 = {'data': [{'e': 55, 'f': 66}, {'g': 77, 'h': 88}]}
outlist = []
for d in item1['data']:
    outlist.append(d)
for d in item2['data']:
    outlist.append(d)
print (outlist)

Output:

[{'a': 11, 'b': 22}, {'c': 33, 'd': 44}, {'e': 55, 'f': 66}, {'g': 77, 'h': 88}]

CodePudding user response：

You can simply try this:

item1 = {'data': [{'a': 11, 'b': 22}, {'c': 33, 'd': 44}]}

item2 = {'data': [{'e': 55, 'f': 66}, {'g': 77, 'h': 88}]}

final = item1.get('data', '')   item2.get('data', '')

print(final)

Output:

[{'a': 11, 'b': 22}, {'c': 33, 'd': 44}, {'e': 55, 'f': 66}, {'g': 77, 'h': 88}]

CodePudding user response：

This is also done by using for loop.

item1 = {'data': [{'a': 11, 'b': 22}, {'c': 33, 'd': 44}]}
item2 = {'data': [{'e': 55, 'f': 66}, {'g': 77, 'h': 88}]}
for item in item2['data']:
    item1['data'].append(item)
print(item1['data'])

CodePudding user response：

Try this script:

a=[]
item1 = {'data': [{'a': 11, 'b': 22}, {'c': 33, 'd': 44}]}
item2 = {'data': [{'e': 55, 'f': 66}, {'g': 77, 'h': 88}]}

for i in range(0,2):

    var1=item1['data'][i]
    a.append(var1)

for i in range(0, 2):
    var1 = item2['data'][i]
    a.append(var1)

print(a)