Pass function argument (dict inside a tuple)-CodePudding

I am writing a function to generate an API url which accept multiple arguments and replicates a part of the string. The short version(which only accept one value for variable Val) looks like this

def get_url(par,att,value, _filter):

    base_url='''https://mytest.com/api/Test/''' str(par) '''?size=100000&filters=['''
    url = base_url   '''{"VarA" : "''' att '''", "Val":["''' value '''"], "VarB":"''' _filter '''"}]'''

    return url


print(get_url('Sales',{'Year':['2020'] , "Time"}))

This will return

https://mytest.com/api/Test/Sales?size=1000&filters=[{"VarA" : "Year", "Val":["2020"], "VarB":"Time"}]

I wrote another function so that I can pass multiple variable for Val while also replicating the filter string using the below function

def get_url(par,argv=None, _filter=None):
    if argv:
        att=argv
        url='''https://mytest.com/api/Test/''' str(par) '''?size=100000&filters=['''
        i=0
        for key in att.keys():
            attribute=key
            attribute_value=att[attribute]
            my_lst_str = '","'.join(map(str, attribute_value))
            values= '"' my_lst_str '"'
            if i==0:
                url=url '''{"VarA" : "''' attribute '''", "Val":[''' value '''], "VarB":''' str(_filter) '''}]'''
            else:url=url ''',{"VarA" : "''' attribute '''", "Val":[''' value '''], "VarB":''' str(_filter) '''}]'''
            i =1

    else:
        url = #Some string#

    return url


url = get_url('Sales',{'Loc':['USA','CAN'],'Year':["2016","2017"]},{'Country','Time'})

But what the above code returns is this

https://mytest.com/api/Test/Sales?size=1000&filters=[{"VarA" : "Loc", "Val":["USA","CAN"], "VarB":"{'Country', 'Time'}"}],{"VarA" : "Year", "Val":["2016","2017"], "VarB":"{'Country', 'Time'}"}]

My expected output is

https://mytest.com/api/Test/Sales?size=1000&filters=[{"VarA" : "Loc", "Val":["USA","CAN"], "VarB":"Country"},{"VarA" : "Year", "Val":["2020","2017"], "VarB":"Time"}]

How do I isolate element for VarB?

CodePudding user response：

You can use your index:

from collections import OrderedDict
def get_url(par, argv=None, _filter=None):
    obj_list, obj_filter = [], list(_filter)
    if argv:
        att = argv
        url = (
            """https://mytest.com/api/Test/"""   str(par)   """?size=100000&filters="""
        )
        i = 0
        for key in att.keys():
            attribute = key
            attribute_value = att[attribute]
            obj_list.append({"VarA" : attribute, "Val": attribute_value, "VarB": obj_filter[i]})
            i  = 1

    else:
        url = "some url"

    return url str(obj_list)


url = get_url(
    "Sales", OrderedDict({"Loc": ["USA", "CAN"], "Year": ["2016", "2017"], "wewe": ["4", "5"]}), {"Country", "Time", "wre"}
)
print(url)

Output:

https://mytest.com/api/Test/Sales?size=100000&filters=[{'VarA': 'Loc', 'Val': ['USA', 'CAN'], 'VarB': 'wre'}, {'VarA': 'Year', 'Val': ['2016', '2017'], 'VarB': 'Time'}, {'VarA': 'wewe', 'Val': ['4', '5'], 'VarB': 'Country'}]