typedef struct grades{
 char s1[DIM];
 char s2[DIM];
 int i;
 float f;

}grades;

void read(grades *s[]);
void write(grades *g[]);
int main() {
    grades v[5];
    read (&v);
    write(&v);
    return 0;
}



void read (grades *s[]){
    printf("enter the name of the student number and point");
    int i;
    for (i=0;i<5;i  ){
        scanf("%s %s %d %f",s[i]->s1,s[i]->s2,s[i]->i,s[i]->f );

    }

}

void write(grades *g[]){
    int i;
    for (i=0;i<5;i  ){
        printf("%s %s %d %f\n",g[i]->s1,g[i]->s2,(g[i]->i) 5,(g[i]->f) 5 );

    }

in this short program, I want to define a struct to get students name, surname, number and then grade. then add 5 grades to their grade and print it. when we use array of structs, should we refer to the array, when we use it with pointer?

CodePudding user response：

You declared an array of structures

grades v[5];

So in this call

write(&v);

the expression &v has the type grades ( * )[5]. This pointer type is not compatible with the functions' parameter type that is implicitly adjusted to grades **g.

You need to declare the functions like

void read(grades *s, size_t n);
void write( const grades *g, size_t n);

and to call the functions like

read( v, 5 );
write( v, 5 );

This call of scanf

scanf("%s %s %d %f",s[i]->s1,s[i]->s2, s[i]->i, s[i]->f );    

shall be rewritten at least like

scanf("%s %s %d %f",s[i].s1,s[i].s2, &s[i].i, &s[i].f );