how to sort a list in a while loop-CodePudding

I want to write a program which reads numbers from the user, until the user enters "0"

and then the program returns the lowest number in that string. I am having trouble sorting out the string.

This is my code so far:

    while True:
    number = []
    number = input("Please enter a number ")

    if number == "0":
        break

number.sort()
x = number[0]
return x

CodePudding user response：

You overwrite your number at each step, this cannot work. You should keep track of the min value instead:

min_value = None
while True:
    number = int(input("Please enter a number ")) # no type check here
    if number == 0:
        break

    if number < min_value:
        min_value = number

print(min_value)

CodePudding user response：

You can make a list of your entered numbers appending them and then finding the minimum value using the numpy module. For example:

import numpy as np

 while True:
     number_list = []
     number = input("Please enter a number ")
     number_list.append(number)

     if number == "0":
     break

 number_array = np.array(number_list)
 minval = np.min(number_array[np.nonzero(number_array)])

So that you can find the minimum value of the array, excluding the "0" you entered at the end.