How to make multiindex dataframe from a nested dictionary keys and lists of values?-CodePudding

I have checked the advicse here:

The code which don't make multiindexes and set every values under each other in next row:

df_a = pd.DataFrame.from_dict(dictionary, orient="index").stack().to_frame()
df_b = pd.DataFrame(df_a[0].values.tolist(), index=df_a.index)

CodePudding user response：

Use ast.literal_eval to convert each string into a dictionary and build the index from there:

import pandas as pd
from ast import literal_eval

dictionary ={
            "{'a': 12.0, 'b': 0.8, 'c': ' bla1'}": [200, 0.0, '0.0'],
            "{'a': 12.0, 'b': 0.8, 'c': ' bla2'}": [37, 44, '0.6'],
            "{'a': 12.0, 'b': 1.8, 'c': ' bla3'}": [100, 2.0, '1.0'],
            "{'a': 12.0, 'b': 1.8, 'c': ' bla4'}": [400, 3.0, '1.0']
            }


keys, data = zip(*dictionary.items())
index = pd.MultiIndex.from_frame(pd.DataFrame([literal_eval(i) for i in keys]))
res = pd.DataFrame(data=list(data), index=index)
print(res)

Output

                  0     1    2
a    b   c                    
12.0 0.8  bla1  200   0.0  0.0
          bla2   37  44.0  0.6
     1.8  bla3  100   2.0  1.0
          bla4  400   3.0  1.0