I've been trying to solve this problem, but I couldn't find a solution.

When I'm copying the RAM usage is more than 2gb or more and than my laptop freezes. What is can I do to free RAM?

This program sorts horizontal and vertical photoes so not a big deal and I'm aware that the code is not the best.

foreach (var srcPath in Directory.GetFiles(sourcePath))
        {
            
            string Name = Path.GetFileName(srcPath);
            //Gets the file's format (like png or jpeg)
            string ext = Path.GetExtension(srcPath);

            bool allowFile = false;

            //This line examines the correct file's format, if it's not correct it won't copy it.
            if (ext == ".png" || ext == ".jpeg" || ext == ".jpg" || ext == ".mp4" || ext == ".PNG" || ext == ".JPEG" || ext == ".JPG" || ext == ".MP4")
                allowFile = true;

            Image img = Image.FromFile(srcPath);

            int width = img.Width;
            int height = img.Height;
           

            if (allowFile)
            {
                if (height > width)
                {
                    File.Copy(srcPath, pathString   "\\"   Name , true);
                }
                else
                {
                    File.Copy(srcPath, pathString2   "\\"   Name, true);
                }
    
                //Copy the file from sourcepath and place into mentioned target path,                    
            }
        }

CodePudding user response：

You need to dispose of your image after using it, in order to free the used memory from the Image.FromFile call.

Try to wrap your image call in a using:

using (Image img = Image.FromFile(srcPath)) 
    {
        int width = img.Width;
        int height = img.Height;

        if (allowFile)
        {
            if (height > width)
            {
                File.Copy(srcPath, pathString   "\\"   Name , true);
            }
            else
            {
                File.Copy(srcPath, pathString2   "\\"   Name, true);
            }

            //Copy the file from sourcepath and place into mentioned target path,                    
        }
    }