I want to call a Python script as a child process from a C program using fork and execv. I have tested it calling bin/ls and it works:
#include <sys/types.h>
#include <sys/wait.h>
#include <unistd.h>
#include <stdio.h>
int main()
{
int status;
char *args[2];
args[0] = "/bin/ls";
args[1] = NULL;
if ( fork() == 0 ){
printf("I am the child\n");
execv( args[0], args ); }
else {
printf("I am the parent\n");
wait( &status ); }
return 0;
}
So I changed the C code to call the Create_Buffer() function in this Python file:
#!/usr/bin/python3
from nltk.corpus import gutenberg
def Create_Buffer():
out_buf = []
pointer = id(out_buf)
value_in = 21
print("I was here")
print(value_in)
return pointer
def NLTK_Python_Libs(n):
if n == 0:
n = n 1
return id(n)
The Python script has two functions; I want to call Create_Buffer(), so I changed my C file to:
#include <sys/types.h>
#include <sys/wait.h>
#include <unistd.h>
#include <stdio.h>
int main()
{
int status;
char * paramsList[] = { "/bin/bash", "-c", "/usr/bin/python", "/opt/P01_SH/NLTK_Gutenberg/NLTK_Python_Libs.Create_Buffer()", (char *)NULL };
if ( fork() == 0 ){
printf("I am the child\n");
execv("/usr/bin/python",paramsList); }
else {
printf("I am the parent\n");
wait( &status ); }
return 0;
}
But I get a syntax error when I run it:
I am the parent
I am the child
File "string", line 1
/usr/bin/python
SyntaxError: invalid syntax
Next I changed it slightly, but I got a different error (described below):
#include <sys/types.h>
#include <sys/wait.h>
#include <unistd.h>
#include <stdio.h>
int main()
{
int status;
char *args[5];
args[0] = "/bin/bash";
args[1] = "-c";
args[2] = "/usr/bin/python";
args[3] = "/opt/P01_SH/NLTK_Gutenberg/NLTK_Python_Libs.Create_Buffer()";
args[4] = NULL;
if ( fork() == 0 ){
printf("I am the child\n");
execv(args[0], args); }
else {
printf("I am the parent\n");
wait( &status ); }
return 0;
}
And this time it invoked the Python command line instead of calling the program:
I am the parent
I am the child
Python 3.8.0 (default, Feb 25 2021, 22:10:10)
[GCC 8.4.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
[ Python command prompt ]
The errors seem to implicate the shebang line at the top of the Python file, but I get the same errors whether I use #!/usr/bin/python, #!/usr/bin/python3 or #!/usr/bin/env python3, or leave the shebang line out.
So my question is: how do I specify the arguments for fork-execv when I want to call a program in a Python .py file? I'm open to using any of the other exec* family, except that I want to use the absolute path, as above, rather than adding to Python PATH, so I don't want to use exec calls with "p" in the name.
I have researched extensively but I haven't found any examples that show the syntax to call a specific program within a Python file and pass arguments to the program. I have seen examples calling a Python file without specifying a program within the file and without passing arguments, but I need to call the function by name.
Compile the C program with:
gcc -fPIC -ggdb -o NLTK_Python.exe NLTK_Python.c -Wall -Wextra
I'm using Python 3.8 on Ubuntu 18.04.
Thanks for any help with this.
CodePudding user response:
I think this is what you want:
#include <sys/types.h>
#include <sys/wait.h>
#include <unistd.h>
#include <stdio.h>
int main()
{
int status;
char * paramsList[] = {
"/usr/bin/python",
"-m",
"NLTK_Python_Libs",
"-c",
"NLTK_Python_Libs.Create_Buffer()",
(char *)NULL };
if ( fork() == 0 ){
printf("I am the child\n");
execv(paramsList[0],paramsList); }
else {
printf("I am the parent\n");
wait( &status ); }
return 0;
}
The -m
option tells it to load the NLTK_Python_Libs
module. Then -c
tells it to execute a function from that module. You can't combine the script pathname with the function name to execute the way you did.
There's no need to use /bin/bash
at all. Just execute python
directly.