[ { "Id": 1, "Value": "Planned Annual" }, { "Id": 2, "Value": "Unplanned annual" }, { "Id": 3, "Value": "Sick Leave" }, { "Id": 4, "Value": "Working From Home" }, { "Id": 5, "Value": "Excuse" }, { "Id": 6, "Value": "Maternity leave" }, { "Id": 7, "Value": "Compassionate Leave" }, { "Id": 1002, "Value": "Additional Leave" } ]

CodePudding user response：

create a model as below :

class APIResponse {
  int id;
  String value;

  APIResponse({this.id, this.value});

  APIResponse.fromJson(Map<String, dynamic> json) {
    id = json['Id'];
    value = json['Value'];
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['Id'] = this.id;
    data['Value'] = this.value;
    return data;
  }
}

Then at API response you can get response like below:

List<APIResposne> list =[];
var result = jsonDecode(response.body);
for(int i=0; i < result.length; i  ){
  list.add(APIResponse.fromjson(result[i]));
}

CodePudding user response：

for converting JSON into model, use dart::convert library and function JsonDecode.

Lets say, your JSON is in variable "json", then the code would look like this:

Map<String, dynamic> your_model_map = jsonDecode(json);

Hope this answered your question, if not, provide us with more description of your issue.

CodePudding user response：

Make Model from:

Following links:

1 jsonToDartModel

2 jsonToDartModel

Generate model class

class APIResponse {
  int id;
  String value;

  APIResponse({this.id, this.value});

  APIResponse.fromJson(Map<String, dynamic> json) {
    id = json['Id'];
    value = json['Value'];
  }

  Map<String, dynamic> toJson() {
    final Map<String, dynamic> data = new Map<String, dynamic>();
    data['Id'] = this.id;
    data['Value'] = this.value;
    return data;
  }
}

Then map it model class if you are using Dio. no need to decode.

final responseData = response.data;
final List<APIResponse> APIResponseList = responseData.map((item) => APIResponse.fromJson(item)).toList()