Indexing Dictionary in a Dictionary in Python-CodePudding

I have the following problem:

Given a dictionary in dictionary:

dict1={"user1":{"id":"1", "link":"http://..."}, "user2":{"id":"2", "link":"http://..."}, ... }

I need:

params = {"user_ids":["1","2", ... ]}

I tried:

params ={
    "user_ids": dict1.values()["id"]
}

but that's not working. It gives an error: 'dict_values' object is not subscriptable.

Is there a way to solve this?

CodePudding user response：

You can use loop. Loop using for loop and each one will be inner dict. Now append all the "ids" in a list. After completion of loop, create a dictionary and print it. Your code:

dict1={"user1":{"id":"1", "link":"http://..."}, "user2":{"id":"2", "link":"http://..."} }
f=[]
for i in dict1:
    f.append(dict1[i]["id"])
f1={"user_ids":f}
print(f1)

Edit you dict1 accordingly

CodePudding user response：

Using a list comprehension:

user_ids = [d['id'] for d in dict1.values()]

Or using operator.itemgetter:

from operator import itemgetter

user_ids = list(map(itemgetter('id'), dict1.values()))

CodePudding user response：

If I understand correctly, then the question is that the keys are in the form user digit, then:

dict1 = {"user1":{"id":"1", "link":"http://..."}, "user2":{"id":"2", "link":"http://..."}}

ids = []

for k, v in dict1.items():
    if 'user' in k:
        for k, v in v.items():
            if k == 'id':
                ids.append(v)

params = {'users_id': ids}
print(params)

result: {'users_id': ['1', '2']}