I have two queries I am running and iterating over both and my final hash is seen below. But, I want to have format on how the data is being stored in the hash that I'm creating or format it after I'm done creating it. But I am not sure how to achieve the desired format where the names
fall under the same id
as show below
desired format of example data:
[
{
id: 1,
accepted: false,
trans: 10234
names: [
{ name: "Joe", amount: "$1,698.00" },
{ name: "Smith", amount: "$674.24" },
]
},
{
id: 2,
accepted: true,
trans: 10234,
names: [
{ name: "Joe", amount: "$1,698.00" },
{ name: "Smith", amount: "$674.24" },
]
}
]
current format I have
[
{
:id => 1,
:accepted => false,
:trans => 8,
:name => "Smith",
:amount => 36.0
},
{
:id => 1,
:amount => false,
:trans => 8,
:name => "Joe",
:amount => 6.0
},
{
:id => 3,
:accepted => false,
:trans => 8,
:name => "Tom",
:amount => 34.0
},
{
:id => 3,
:accepted => false,
:trans=> 8,
:name => "Martha",
:amount => 4.0
}
],
[
{
:id => 2,
:accepted => true,
:trans => 7,
:name => "Bob",
:amount => 35.0
},
{
:id => 2,
:accepted => true,
:trans => 7,
:name => "John",
:amount => 5.0
}
]
logic for creating hash
imports = ListImports.limit(20).order(created_at: :DESC)
groups = imports.map{|import| ListImportGroup.where(list_import_id: import.id)}
pub_hash_true = []
pub_hash_false = []
hash = []
imports.map do |import|
hash << {
id: import.id,
trans: import.trans,
accepted: import.amount
}
end
hash.each do |import|
groups.flatten.each do |group|
accepted = import[:accepted]
num_transactions = import[:trans]
if accepted == false
pub_hash_false << {id: import[:id], accepted: accepted, trans: num_transactions, name: group.name, amount: group.amount}
else
pub_hash_true << {id: import[:id], accepted: accepted, trans: num_transactions, name: group.name, amount: group.amount}
end
end
end
CodePudding user response:
# Note: You didn't specify what is the association between `ListImport` and `ListImportGroup`.
# However, I'm fairly sure you could be fetching this data via a JOIN query like below,
# rather than making up to 20 additional database calls to fetch the associated records.
imports = ListImports.limit(20).order(created_at: :DESC).includes(:list_import_group)
result = imports.map do |import|
{
id: import.id,
trans: import.trans,
accepted: import.amount,
names: import.list_import_groups.pluck(:name, :amount)
}
end
And if you do actually need to filter for imports where accepted
is true
or false
, you could do something like this instead of building separate arrays manually:
accepted_imports = result.select { |import| import[:accepted] }
# and
rejected_imports = result.reject { |import| import[:accepted] }
# or even:
accepted_imports, rejected_imports = result.partition { |import| import[:accepted] }
CodePudding user response:
You didn't specify the exact correspondence between the desired and current formats. But I assume
- For the entries with the same
id
, the values ofaccepted
andtrans
are identical. - the desired amount for Joe in the current format is identical in the corresponding amount in the desired amount. (In your example, the former is
6.0
whereas the latter is"$1,698.00"
, which does not make sense.)
Then, the following would do the conversion. The array ahout
is in the desired format.
# Let us assume "a1" is the original array in the "current format"
hout = {}
a1.flatten.map{|h|
h.slice(*(%i(id trans name amount accepted))).values
}.each{ |a|
hout[a[0]] = {id: a[0], accepted: a[4], trans: a[1], names: []} if !hout.key? a[0]
hout[a[0]][:names].push(
{name: a[2], amount: "$" helper.number_with_precision(a[3], precision: 2, delimiter: ',')}
)
}
ahout = hout.values
You may want to sort ahout
, if you like.
Note that I am assuming you are using Rails 5 . Otherwise, the method helper
may not work. In that case, you can use sprintf
or whatever formatting method.