The brief is to input 10 salaries, compute commission, and overall take home, and print highest takehome. I am able to get the highest number, but for the number inputted, and not for the takehome (which I calculate). I wonder how I do this as I'm not storing the take home values I'm calculating? Is this my issue? Please see code below.

#include <stdio.h>
 
int main()
{
    int num[10];
    int i = 0;
    int largest;
    int com, totaltakehome, finalsalary;
         
    while(i < 10)
    {
        printf("Enter salesperson salary for week[%d]:", i   1);
        scanf("%d", &num[i]);
        com = num[i] / 100 * 7;
        printf("Commision is %d\n", com);
        totaltakehome = 300   com;
        printf("Total takehome is %d\n", totaltakehome);
        printf("\n");
    }

    largest = num[0];
    i = 0;
    while(i < 10)
    {
        if(num[i] > largest)
        {
            largest = num[i];
        }
        i  ;
    }

    printf("\nHighest salary is : %d\n", largest);

    return 0;
}

CodePudding user response：

Since none of the previously entered salaries are needed to calculate ...

• the largest commission
• the total takehome

... you can skip the num[10] array.

• You do need to increase i in the loop. i 1 is an expression which does not change the value of i. I suggest using a for loop for this which keeps the declaration of i, the condition (i < 10) and the increment nicely in one place.
• You should check the return value from scanf. If you scan for one thing, it should return 1, otherwise it failed.
• Save the largest commission in the loop.
• Initialize variables.
• Add to totaltakehome. You currently assign a new value to it in every loop.

Example:

#include <stdio.h>

int main() {
    int largest = 0;       // initialized (and assuming this can't be negative)
    int totaltakehome = 0; // initialized

    for(int i = 0; i < 10;   i) {  // loop with increment
        printf("Enter salesperson salary for week[%d]:", i   1);

        int num;
        if(scanf("%d", &num) != 1) {   // check for success
            fprintf(stderr, "user error, aborting\n");
            return 1;
        }

        // an alternative commission forumla
        int com = num * 7 / 100; // perhaps a more fair commission

        printf("Commision is %d\n", com);

        // save this commission if it's the largest so far:
        if(com > largest) largest = com;

        // Add to `totaltakehome` - don't assign:
        totaltakehome  = 300   com;    // note: ` =`, not `=`

        printf("\n");
    }

    // print results after the loop:
    printf("Largest commision %d\n", largest);
    printf("Total takehome is %d\n", totaltakehome);
}

CodePudding user response：

We can use a basic for loop for the answer.

int old = arr[0];
for (i = 0; i < 10; i  ) {
    if (arr[i] > old) old = arr[i];
}

return old;

First we create a loop that runs ten times or we can also use

sizeof(arr)/sizeof(arr[0])

For an unknown list type. Forgive me for I am on mobile.

Then we check if the next number is bigger than our old biggest known if so set it to be the biggest. If so, we will set it to be our biggest. Then we finally return our value. (This is a function btw)