How to replace "$10" with "10 dollars" using regex?-CodePudding

I have some phrases like below:

This is not my spending '$10', this is companys spending: '$250 million' and this is some other figure: '$200,000'.

that I would like to remove the dollar symbols and add "dollar" at the end of phrase, like this:

This is not my spending '10 dollars', this is companys spending: '250 million dollars' and this is some other figure: '200000 dollars'.

I now have regex to match([£\$€][\s\d,\d] (|million|billion|trillion)), but I haven't been able to get the substitution part right.

How do I do this?

CodePudding user response：

You may use the following function to achieve what you described.

import re

def adjust_dollars(text):
  text = re.sub(r'^\$', '', text)
  text = re.sub(r'(.$)', r'\1 dollars', text)
  return text

Test run:

words = ['$10', '$250 million', '$200,000']
result = map(adjust_dollars, words)
print(list(result))

Output:

['10 dollars', '250 million dollars', '200,000 dollars']

CodePudding user response：

Just an example with re.sub:

t1 = "$10"
t2 = "$250 million"
t3 = "$200,000"

sub_pattern = "/$|," #Look for dollar signs or commas
tail = " dollars"
re.sub(sub_pattern,"",t1)   tail -> 10 dollars
re.sub(sub_pattern,"",t2)   tail -> 250 million dollars
re.sub(sub_pattern,"",t3)   tail -> 200000 dollars

CodePudding user response：

Since your regex also includes symbols for Pound and Euro, I assume not all of those start with $. Then you could use re.sub with a callback-function to determine the currency to use. This also works if the currencies appear in the middle of the text.

import re
p = "([£\$€])\s?([,\d] (?: million| billion| trillion|))"
d = {"$": "dollars", "£": "pounds", "€": "euros"}

text = "I have $10 and £3 million and €100,000 trillion"
print(re.sub(p, lambda m: f"{m.group(2)} {d[m.group(1)]}", text))
# I have 10 dollars and 3 million pounds and 100,000 trillion euros

Also note some subtle changes to the regex: I put the currency symbols in a group, so it can be accessed later, and put the "empty" suffix at the end, otherwise it's greedily matched first and none of the others. Also, no need to put \d twice in [...], and better move the space to the suffix part.

CodePudding user response：

If all of your strings start with "$" you don't need to use regex. just select them at second character with "[1:]" and add " dollars" at the end. for example if your string store in variable named a:

a[1:]   " dollars"